We want to find in how many ways two families can sit in the movie theater.
We will find that there are 1,152 different ways to sit.
First, let's find the number of ways in which a single family can sit together. There are 4 chairs and 4 members of the family.
On the first chair, there are 4 options (4 members to sit on it).
On the second chair, there are 3 options (because someone already took the first chair).
On the third chair, there are 2 options.
On the last chair, there is only one option.
The number of different combinations is given by the product between the numbers of options, we get:
C = 4*3*2*1 = 24
Now, we have two families A and B, so the total number of combinations now is:
C' = 24*24 = 576
And the families can also permute, so we have 2 possible permutations (family A goes first or family B goes first).
Then the total number of combinations is:
combinations = 2*C' = 2*576 = 1,152
If you want to learn more, you can read:
https://brainly.com/question/2471227
