Answer:
Step-by-step explanation:
a=3 b=5 c=8
solve the equations---
Section A :
1) ab+3c = (3)(5)+3(8) = 15+24 = 39
[tex]ab + 3c = (3)(5) + (3)(8)=15+24=39[/tex]
2) 2a-3b = 2(3) - 3(5) = 6 - 15 = -9
[tex]2a-3b=2(3)-3(5)=6-15=-9[/tex]
3) 2(a+b) - c squared = 2(3+5) - 8 squared = 2(8) - 64 = 16 - 64 = -48
[tex]2(a+b) - c^{2} = 2(3+5) - 8^{2} =2(8) - 64 = 16 - 64 = -48[/tex]
4) 3a x 2b + 4c = 3(3) x 2(5) + 4(8) = 9 x 10 + 32 = 90 + 32 = 122
5) a squared - 2c = 3 squared - 2(8) = 9 - 2(8) = 9 - 16 = -7
[tex]a^{2} -2c = 3 ^{2} - 2(8) = 9 - 2(8) = 9 - 16 = -7[/tex]
simplify the expressions---
- pretty much distribute
Section B :
1) a(2a+b) = 2a squared + ab
[tex]a(2a+b)=\\2a^{2} + ab[/tex]
2) 3(3g - 4) = 3 squared g - (3)4 = 9g - 12
[tex]3 (3g-4)=\\3^{2} g - (3)4 =\\9g - 12[/tex]
3) 2a(4b - 2ad) = 8ab - 4a squared d
[tex]2a(4b-2ad) = \\8ab-4a^{2} d[/tex]
4) -3ab(1 +5a) = -3ab -15a squared b
[tex]-3ab(1+5a)= \\-3ab - 15a^{2} b[/tex]
5) k(3k + 14) = 3k squared + 14k
[tex]k(3k + 14)=\\3k^{2} +14k[/tex]
hope this helps!
mark me brainliest :D
