There is a line that includes the point(10, 5)and has a slope of 1 What
is its equation in slope-intercept form?So far I have y=1x+what's the y?

Respuesta :

Answer:

y = x - 5

Step-by-step explanation:

Given the point, (10, 5), and the slope, m = 1:

Substitute these values into the slope-intercept form to solve for the y-intercept, b:

y = mx + b

5 = 1(10) + b

5 = 10 + b

Subtract 10 from both sides to isolate b:

5 - 10 = 10 - 10 + b

-5 = b

The y-intercept of the line is: b = -5. This represents the y-coordinate of the y-intercept, (0, -5), which represents the point on the graph where it crosses the y-axis. Along the y-axis, the value of x = 0. Hence, the y-intercept is (0, -5).  

Therefore, given the slope, m = 1, and the y-intercept, b = -5:

The equation of the line in slope-intercept form is:  y = x - 5.