Trucker8120
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The tiny planet Mercury has a radius of 2400 km and a mass of 3.3 times 10^23 kg.
a) What would be the gravitational acceleration of an astronaut standing on
the surface of Mercury? b) Compare the motion of a ball dropped on the
surface of Mercury to that of a ball dropped on Earth.

Respuesta :

nooris0663

Answer:

I think that you need the gravitational acceleration of mercury

so we will use Newton's gravitational law :

gravitational acceleration = G*m/2

G is the gravitational constant = G = 6.673×10^-11 N m^2 kg^-2

after substitution : m^7x r67 / 11

6.673×10^-11 * 3.2x10^23 / (2.43x10^6)^2

using calculator : 2.00007899999

gravitational acceleration of mercury = 3.61625 m/s^2

pls give me brainliest

Explanation:

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