A company makes a profit of $y (in thousand dollars) when it produces x computers,
where y is given by the formula y = a(x - 100)(x - 200) for x 20 If 120
computers are produced, the profit will be $3,200,000.
a) Find the value of a.

b) What is the maximum profit the company can make? At this profit, how many
computers should be produced?

c) If the company targets to make at least $4,800,000, what is the range of the
number of computers to be produced?


Respuesta :

The solutions to the questions if y is represented by the formula y = a(x - 100)(x - 200) are:

a) The value of a = -2000

b) The maximum profit the company can make = $5,000,000

To make maximum profit, 150 computers must be produced

c) The company must produce between 140 and 160 computers to make at least $4,800,000

The equation representing the company's profit is:

y = a(x - 100)(x - 200)  for x > 20

If 120  computers are produced, the profit will be $3,200,000

That is, y = 3,200,000 if x = 120

a) Find the value of a

3,200,000 = a(120 - 100)(120 - 200)

3200000 = -16000a

a = -3200000/1600

a = -2000

b) Maximum profit the company can make

The equation becomes:

y = -2000(x - 100)(x - 200)

y = -2000(x² - 200x - 100x + 20000)

y = -2000(x² - 300x + 20000)

y = -2000x² + 600000x - 40000000

dy/dx = -4000x + 600000

dy/dx = 0 at maximum value

-4000x  +  600000 = 0

4000x  =  600000

x  =  600000/4000

x   =  150

To make maximum profit, 150 computers must be produced

Substitute x = 150 into y = -2000x² + 600000x - 40000000 to find the maximum profit

y  = -2000(150²) + 600000(150) - 40000000

y = 5000000

The maximum profit the company can make = $5,000,000

c) Calculate the range of the number of computers to be produced If the company targets to make at least $4,800,000

-2000x² + 600000x - 40000000 ≥ 4800000

-2000x² + 600000x - 40000000 - 4800000 ≥ 0

-2000x² + 600000x - 44800000 ≥ 0

Divide through by -2000

x² - 300x +22400 ≤ 0

(x - 140)(x - 160) ≤ 0

140 ≤ x ≤ 160

The company must produce between 140 and 160 computers to make at least $4,800,000

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