Answer:
[tex]0.225 \Omega =225 m\Omega[/tex]
Step-by-step explanation:
We know (Ohm second law) that [tex]R= \frac{k}{d^2}[/tex] where k inlcudes the rest of the parameters (material, lenght). In our situation we have k= [tex]0.4\cdot9 \Omega mm^2[/tex]. The moment the diameter becomes 8mm R becomes
[tex]R= {{0.4\cdot 9}\over{16}} \Omega = 0.225 \Omega[/tex]