Answer:
x= 16
Step-by-step explanation:
combine multiplied terms into a single fraction
[tex]\frac{1}{2} (x-4)=\frac{1}{3} (x+2)[/tex]
[tex]\frac{1(x-4)}{2} =\frac{1}{3} (x+2)[/tex]
Multiply by 1
[tex]\frac{1(x-4)}{2} =\frac{1}{3} (x+2)[/tex]
[tex]\frac{x-4}{2} =\frac{1}{3} (x+2)[/tex]
Combine multiplied term into a single fraction
[tex]\frac{x-4}{2} =\frac{1(x+2)}{3}[/tex]
Multiply by 1
[tex]\frac{x-4}{2} =\frac{x+2}{3}[/tex]
Multiply all terms by the same value to eliminate fraction denominators
[tex]6*\frac{x-4}{2} 6(\frac{x+2}{3} )[/tex]
cancel multiplied terms that are in the denominator
[tex]3(x-4)=2(x-2)[/tex]
Distribute
[tex]3x-12=2(x+2)[/tex]
Distribute
[tex]3x-12=2x+4[/tex]
Add 12 to both sides of the equation
[tex]3x-12+12=2x+4+12[/tex]
Simplify
[tex]3x=2x+16[/tex]
Subtract 2x from both sides of the equation
[tex]3x=2x=2x+16-2x[/tex]
Simplify
[tex]x=16[/tex]
