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A rock climber’s shoe loosens a rock, and her climbing buddy at the bottom of the cliff notices that the rock takes 3.20 s to fall to the ground. How high up the cliff is the rock climber?

Respuesta :

evgeniylevi

Answer:

50.176 [m].

Explanation:

1) the required height can be calculated using the formula:

h=V₀*t+1/2* g*t₂, where V₀ - initial velocity of the rock, t - elapsed time, g - 9.8 m/s²;

2) if V₀=0, t=3.2, g=9.8, then

h=0.5*9.8*3.2²=1024*49*10⁻³=50.176 [m].≈50[m].

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