Considering the ideal gas law, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.
Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P× V = n× R× T
In this case, you know:
Replacing:
2 atm× V = 4.745 moles× 0.082[tex]\frac{atmL}{molK}[/tex]× 353 K
Solving:
V = (4.745 moles× 0.082[tex]\frac{atmL}{molK}[/tex]× 353 K)÷ 2 atm
V= 68.67 L
Finally, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.
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