contestada

Given: \overline{AE} \parallel \overline{FD},

AE

∥

FD

, \overline{BF} \parallel \overline{EC}

BF

∥

EC

and \overline{AC} \cong \overline{BD}.

AC

≅

BD

.


Prove: \triangle AEC \cong \triangle DFB△AEC≅△DFB.
needed 3 prove (angle/slide)

Given overlineAE parallel overlineFD AE FD overlineBF parallel overlineEC BF EC and overlineAC cong overlineBD AC BD Prove triangle AEC cong triangle DFBAECDFBn class=

Respuesta :

Answer:

See below for answer.

Step-by-step explanation:

∠ECB ≅ ∠FBC    Parallel lines cut by a transversal form congruent alternate  

                             interior angle  

Δ AEC ≅ Δ DFB   ASA                

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