Answer:
Q9: C.
Since each smaller line counts as 1/5, you can simply start from the point 1 and count 3 times to reach D.
[tex]3*\frac{1}{5} =\frac{3}{5}[/tex]
Since you started at 1, you can add [tex]1+\frac{3}{5} =1\frac{3}{5}[/tex]
Q10: B
We can subtract/ignore 3 from all of them to make things simpler.
Now, we need to find the lowest value to greatest from:
[tex]\frac{5}{8}, \frac{7}{16} ,\frac{1}{2}[/tex]
In order to compare these, we make the denominators the same (in this case: 16)
[tex]\frac{5}{8} =\frac{5*2}{8*2} =\frac{10}{16}[/tex]
[tex]\frac{7}{16} =\frac{7}{16}[/tex]
[tex]\frac{1}{2} =\frac{1*8}{2*8} =\frac{8}{16}[/tex]
Since 7 is the smallest value, followed by 8 and lastly 10,
the smallest to greatest in order would be
[tex]\frac{7}{16} ,\frac{1}{2} ,\frac{5}{8}[/tex] (B)
11: C
If you look at both [tex]\frac{2}{4}[/tex] and [tex]\frac{5}{8}[/tex], they are not directly above one another. Hence, they are not equal.
