How many grams of solute are needed to order to prepare 100.00 mL of a 0.1000 M solution of a compound with a molecular weight of 350.0 g/mol

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Answer:

i got 35 but i am as lost as you are so don't really take my answer as a trusted answer

The grams of solute are required.

The mass of solute is 3.5 g

c =  Molarity = 0.1 M

M = Molar mass = 350 g/mol

V = Volume of solution = 100 mL = 0.1 L

n = Number of moles

m = Mass of solute

Molarity is given by

[tex]c=\dfrac{n}{V}\\\Rightarrow n=cV\\\Rightarrow n=0.1\times 0.1\\\Rightarrow n=0.01\ \text{moles}[/tex]

Molar mass is given by

[tex]M=\dfrac{m}{n}\\\Rightarrow m=Mn\\\Rightarrow m=350\times 0.01\\\Rightarrow m=3.5\ \text{g}[/tex]

The mass of solute is 3.5 g

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