contestada

Write an exponential equation in the form y = ab^x whose graph passes through points (1,0.84) and (2,1.008)

Respuesta :

Answer:

y = 0.7 * 1.2^x

Step-by-step explanation:

(1, 0.84)

0.84 = ab^1

(2, 1.008)

1.008 = ab^2

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To find b divide the second point by the first

ab^2 / ab^1 = 1.008 / 0.84

b = 1.2

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To find a plug b = 1.2 into the first point

0.84 = a * 1.2^1

0.84 = a * 1.2

Divide both sides by 1.2

0.7 = a

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The equation is

y = 0.7 * 1.2^x