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What will the final temperature of the a block of brass with a mass of 30.6 g is at 87.4°C
after it's added to 62.3 g of water at 28.3°C. The specific heat of aluminum is 0.380
J/gºC.

Respuesta :

samueladesida43

The final temperature of the block of brass with a mass of 30.6 g at 87.4°C is 30.82°C.

SPECIFIC HEAT CAPACITY:

  • The amount of heat absorbed or released by a substance can be calculated using the following formula:

  • Q = m × c × ∆T

  • Q(water) = - Q(metal)

  • (m × c × ∆T) water = - (m × c × ∆T) metal

According to this question;

METAL:

  1. m = 30.6g
  2. c = 0.380 J/g°C
  3. ∆T = T - 87.4°C

WATER:

  1. m = 62.3g
  2. c = 4.184J/g°C
  3. ∆T = T - 28.3°C

  • 62.3 × 4.184 × (T - 28.3) = - {30.6 × 0.380 × (T - 87.4)}

  • 260.7T - 7376.8 = - {11.63T - 1016.3}

  • 260.7T - 7376.8 = -11.63T + 1016.3

  • 260.7T + 11.63T = 1016.3 + 7376.8

  • 272.33T = 8393.1

  • T = 8393.1 ÷ 272.33

  • T = 30.82°C

  • Therefore, the final temperature of the block of brass with a mass of 30.6 g at 87.4°C is 30.82°C.

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