Solving for x...
[tex] \frac{1}{2} x+ \frac{1}{4} = \frac{15}{16}
[/tex]
Times the [tex] \frac{1}{2} [/tex] , both the numerator and denominator, by 8 to get the denominator to 16.
Times the [tex] \frac{1}{4} [/tex] , both the numerator and denominator, by 4 to get the denominator to 16.
Then rewrite the problem,
[tex] \frac{8}{16}x+ \frac{4}{16} = \frac{15}{16} [/tex]
now that the denominators are all the same, you can solve...
subtract the [tex] \frac{4}{16} [/tex] from both sides
you should get [tex] \frac{8}{16} x = \frac{11}{16} [/tex]
Multiply both sides by 16 (it'll cancel both the 16 out making it go away)
8x = 11
divide each side by 8 to have the x alone
8x = 11
8 8
You should end with x = [tex] \frac{11}{8} [/tex] or 1.375
