Answer : The correct option is, 112 ml
Solution : Given,
Mass of [tex]SO_2[/tex] = 0.640 g
Molar mass of [tex]SO_2[/tex] = 64 g/mole
First we have to calculate the moles of [tex]SO_2[/tex].
[tex]\text{Moles of }SO_2=\frac{\text{Mass of }SO_2}{\text{Molar mass of }SO_2}=\frac{0.640g}{64g/mole}=0.01moles[/tex]
Now we have to calculate the moles of oxygen gas.
The balanced chemical reaction will be,
[tex]2SO_2+O_2\rightarrow 2SO_3[/tex]
From the reaction, we conclude that
As, 2 moles of [tex]SO_2[/tex] react with 1 mole of [tex]O_2[/tex] gas
So, 0.01 moles of [tex]SO_2[/tex] react with [tex]\frac{0.01}{2}=5\times 10^{-3}[/tex] mole of [tex]O_2[/tex] gas
Now we have to calculate the volume of oxygen gas.
As, 1 mole of oxygen gas contains 22400 ml volume of oxygen gas
So, [tex]5\times 10^{-3}[/tex] mole of oxygen gas contains [tex]22400ml\times (5\times 10^{-3})=112ml[/tex] volume of oxygen gas
Therefore, the volume of oxygen gas is, 112 ml
