Respuesta :

apologiabiology
so listen to this logic
lets say you have 3 numbers, m,a,x where they are all positivie
m>a>x
therefor
m^2>a>2>x^2
if m and a and x are square roots, therefor we can reverse the square root
confusing sorry

square 5 and 6
5^2=25
6^2=36

the number betwe 25 and 36

that would be 32

answer is √32

goes like this
5^2<32<6^2
sqrt both sides
5<√32<6

answer is √32

Answer:

[tex]\sqrt{32}[/tex]

Step-by-step explanation:

expressions has a value between 5 and 6.

First we take perfect square numbers

WE know [tex]\sqrt{25} = 5[/tex]

[tex]\sqrt{36} = 6[/tex]

We need to find a value between 5  and 6

That means we need to find a value between [tex]\sqrt{25} \  and \ \sqrt{36}[/tex]

[tex]\sqrt{17}[/tex] does not lie between [tex]\sqrt{25} \ and \ \sqrt{36}[/tex]

[tex]\sqrt{32}[/tex]  lie between [tex]\sqrt{25} \ and \ \sqrt{36}[/tex]

[tex]\sqrt{60}[/tex] does not lie between [tex]\sqrt{25} \ and \ \sqrt{36}[/tex]

[tex]\sqrt{1125}[/tex] does not lie between [tex]\sqrt{25} \ and \ \sqrt{36}[/tex]

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