Victor has a credit card with an APR of 13.66%, compounded monthly. He currently owes a balance of $1,349.34. Assuming that Victor makes no purchases or payments, how much will he owe after one year, to the nearest cent?

Respuesta :

A = P (1 + r/n)^nt
A = 
1,349.34(1+0.1366/12)^12
A = 1545.65

answer: 
he will owe $1545.65 after one year

Answer:

$1545.65.

Step-by-step explanation:

We have been given that Victor has a credit card with an APR of 13.66%, compounded monthly. He currently owes a balance of $1,349.34.

To solve our given problem we will use compound interest formula.

[tex]A=P(1+\frac{r}{n})^{nt}[/tex], where,

A = Final amount after t years,

P = Principal amount,

r = Interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

Let us convert our given interest rate in decimal form.

[tex]13.66\%=\frac{13.66}{100}=0.1366[/tex]

Upon substituting our given values in compound interest formula we will get,

[tex]A=\$1,349.34(1+\frac{0.1366}{12})^{12*1}[/tex]

[tex]A=\$1,349.34(1+0.011383333)^{12}[/tex]

[tex]A=\$1,349.34(1.011383333)^{12}[/tex]

[tex]A=\$1,349.34*1.145485275522[/tex]

[tex]A=\$1,545.64910167397\approx \$1545.65[/tex]

Therefore, Victor will owe an amount of $1545.65 after one year.