A master electrician earns $62 per hour. His apprentice earns $40 per hour. The master electrician works 3 hours more than the apprentice. If together they are paid $492, how much does the master electrician earn?

Respuesta :

x=hours master worked
y=hours apprentice worked


62x+40y=492

if master worked 3hours more than apprntice
x=3+y

sub 3+y for x

62(3+y)+40y=492
expand
186+62y+49y=492
186+102y=492
minus 186 both sides
102y=306
divide both sides by 102
y=3

sub back
x=3+y
x=3+3
x=6

master electrician worked 6 hours
6*62=372

master electrician earned $372

Answer:

$372

Step-by-step explanation:

Let x = master electrician's hours

Let y = apprentice's hours

Since the master electrician worked 3 hours more than the apprentice, x - 3 = y.

Set up the system of equations.

x - 3 = y

62x + 40y = 492

In the second equation, substitute x - 3 in for y and solve for x (hours worked by master electrician).

62x + 40(x - 3) = 492

62x + 40x - 120 = 492

102x = 612

x = 6 hours

Multiply 6 by the hourly rate of $62.

The master electrician earns $372.