Considering the reaction stoichiometry and Avogadro's Number, the mass of barium chloride produced is 21.6 grams.
The balanced reaction is
2 HCl + Ba → BaCl₂ + H₂
Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of HCl, then 1.25×10²³ molecules are contained in how many moles of HCl?
amount of moles of HCl= (1.25×10²³ molecules × 1 mole)÷ 6.023×10²³ atoms
amount of moles of HCl= 0.2075 moles
Then, 0.2075 moles of HCl react.
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl produce 1 mole of BaCl₂, 0.2075 moles of HCl will produce how many moles of BaCl₂?
[tex]amount of moles of BaCl_{2} =\frac{0.2075 moles of HCl x 1 mole of BaCl_{2} }{ 2moles of HCl}[/tex]
amount of moles of BaCl₂= 0.10375 moles
Being the molar mass of BaCl₂ 208.24 g/mole, then the mass of barium chloride produced is calculated as:
[tex]0.10375 molesx\frac{208.24 grams}{1 mole} =21.6 grams[/tex]
Finally, the mass of barium chloride produced is 21.6 grams.
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