Answer:
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Explanation:
The concentration of hydroxide ion (-OH) in 1.37 x10^-5 m solution of Ba(OH)2 is calculated as follows
write the equation for dissociation of Ba(OH)2
Ba(OH)2 = Ba^2+(aq) + 2OH^-(aq)
by use of mole ratio between Ba(OH)2 to OH^- which is 1:2 the concentration of OH^- = 2x ( 1.37 x10^-5) = 2.74 x10^-5 M