Respuesta :

  • Atomic weight of copper = 63.5 g
  • 1 mole of copper contains = 63.5g = 6.023 × 10²³ atoms of copper
  • 1 g of copper contains
  • [tex] = \frac{ 6.023 \times 10²³}{63.5} [/tex]= 9.4 × 10²¹ atoms
  • Therefore, 3.11g of copper contains
  • [tex] = 3.11 \times 9.4 \times {10}^{21} \\ [/tex]
  • = 29.234 × 10²¹ atoms

Hope you could get an idea from here.

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