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What is the required mass to prepare a 0.5M potassium chloride solution using 250mL of water

Respuesta :

Molarity - It is defined as number of moles of solute in the given solution.

Molarity = number of moles / Volume of solution

moles = mass / molecular weight

Molecular weight of KCl =( K-39) + (Cl -35.5) = 74.5 g/mole

Volume of soultion = 250 mL = 0.25L

Molarity = 0.5 M

Now ,

Molarity = number of moles / volume of solution

= Mass of KCl / molecular weight of KCl × Volume

0.5 = Mass of KCl / 74.5 × 0.25

Mass of KCl = 0.5 × 74.5 × 0.25 = 9.3125 grams

Hence the mass of KCl required is 9.3125 grams.