N2O5
Explanation!When given %, assume you have 100 g of the substance. Find moles, divide by lowest count. In this case you'll end up with
25.92 g N14.01 g N/mol N=1.850 mol N
74.07 g O16.00 g O/mol O=4.629 mol O
The ratio between these is 2.502 mol O/mol N, which corresponds closely with N2O5.
Answer: [tex]N_2O_5[/tex]
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of N = 25.92 g
Mass of O = 74.07 g
Step 1 : convert given masses into moles.
Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{25.92g}{14g/mole}=1.85moles[/tex]
Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{74.07g}{16g/mole}=4.63moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For N = [tex]\frac{1.85}{1.85}=1[/tex]
For O =[tex]\frac{4.63}{1.85}=2.5[/tex]
The ratio of Fe : O= 1:2.5
Converting them into whole numbers, the ratio will be 2: 5
Hence the empirical formula is [tex]N_2O_5[/tex]
