The function y = 2x^2 + 6x + 3 is a quadratic function that has a vertex of (-1.5,-1.5)
How to determine the graph of the function?
The equation of the function is given as:
y = 2x^2 + 6x + 3
Differentiate
y' = 4x + 6
Set to 0
4x + 6 = 0
This gives
4x = -6
Divide by 4
x = -1.5
Substitute x = -1.5 in y = 2x^2 + 6x + 3
y = 2(-1.5)^2 + 6(-1.5) + 3
Evaluate
y = -1.5
This means that the function y = 2x^2 + 6x + 3 has a vertex of (-1.5,-1.5)
See attachment for the graph of y = 2x^2 + 6x + 3
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