Mike wants to fence in part of his backyard. He wants the length of the fenced-in area to be at least 20 feet long, l ≥ 20. He has 200 feet of fencing. The inequality that models the possible perimeter of the yard is 2l 2w ≤ 200. Which are possible dimensions for Mike’s backyard? Check all that apply. W = 50 ft; l = 10 ft w = 10 ft; l = 50 ft w = 20 ft; l = 60 ft w = 90 ft; l = 30 ft w = 50 ft; l = 40 ft.

Respuesta :

The inequality that models the possible perimeter of the yard is 2(l + w) ≥ 200

The possible dimension of the width is 90 feet

The formula for calculating the perimeter of the fence is expressed as:

  • P = 2(l + w)

  • l is the length of the fence
  • w is the width of the fence

If he has 200 feet of fencing, then:

2(l + w) ≥ 200

If the length of the fenced-in area to be at least 20 feet long, the equation becomes:

2(20 +w) ≥ 200

40 + 2w ≥ 200

2w ≥  200 - 40

2w≥ 160

w≥  80

Hence the possible dimension of the width is 90 feet

Learn more on inequalities here: https://brainly.com/question/10709615

Answer:

bce

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