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An airplane initially travels at 12 m/s when passing the "acceleration line." The airplane then
accelerates to 9 m/s2 until reaching its take off velocity of 40.0 m/s. What is the displacement of
the plane during the acceleration?

Respuesta :

Lanuel

The displacement of  the plane during the acceleration is equal to 80.89 meters.

Given the following data:

  • Initial velocity = 12 m/s
  • Final velocity = 40 m/s
  • Acceleration = 9 [tex]m/s^2[/tex]

To determine the displacement of  the plane during the acceleration, we would use the third equation of motion;

[tex]V^2 = U^2 + 2aS[/tex]

Where:

  • V is the final speed.
  • U is the initial speed.
  • a is the acceleration.
  • S is the displacement traveled.

Substituting the given parameters into the formula, we have;

[tex]40^2 =12^2 + 2(9)S\\\\1600=144+18S\\\\18S=1600-144\\\\18S=1456\\\\S=\frac{1456}{18}[/tex]

Displacement, S = 80.89 meters.

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