Respuesta :
The average travel time is simply the mean travel time between the given points
- The average time that it takes for the car to travel the first 0.25m is 2.23s.
- The average time to travel just between 0.25m and 0.50m is 0.9s.
- Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.
(a) The average time to travel the first 0.25m
The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.
So, the average time to travel is:
[tex]Time = \frac{2.24s + 2.21s + 2.23s}{3}[/tex]
[tex]Time = \frac{6.68s}{3}[/tex]
[tex]Time = 2.23s[/tex]
(b) The average time to travel just between 0.25m and 0.50m
The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.
So, the average time to travel this distance is:
[tex]Time = \frac{3.16s + 3.08s + 3.15s}{3}[/tex]
[tex]Time = \frac{9.39s}{3}[/tex]
[tex]Time = 3.13s[/tex]
The average time to travel between both distance is the difference between the average time of each distance.
So, we have:
[tex]Average = 3.13s - 2.23s[/tex]
[tex]Average = 0.9s[/tex]
(c) The velocity in the second 0.25m section
The distance and time are:
[tex]Distance = 0.25m[/tex]
[tex]Time = 0.9s[/tex]
So, the velocity is:
[tex]Velocity = \frac{Distance}{Time}[/tex]
This gives
[tex]Velocity = \frac{0.25m}{0.9s}[/tex]
[tex]Velocity = 0.28m/s[/tex]
Read more about distance, velocity and time at:
https://brainly.com/question/4931057
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