Using the arrangement formula, it is found that there are [tex]28! = 3.05 \times 10^{29}[/tex] possible seating arrangements.
The number of possible arrangements of n elements is given by the arrangement formula, as follows:
[tex]A_n = n![/tex]
In this problem, 28 students are arranged on 28 desks, hence [tex]n = 28[/tex], and:
[tex]A_{28} = 28! = 3.05 \times 10^{29}[/tex]
Hence, there are [tex]28! = 3.05 \times 10^{29}[/tex] possible seating arrangements.
You can learn more about the arrangement formula at https://brainly.com/question/24648661