Given that △ABC is an isosceles triangle with AB⎯⎯⎯⎯⎯≅AC⎯⎯⎯⎯⎯ and AD⎯⎯⎯⎯⎯ bisecting ∠BAC, which of the following proves that ∠ABD≅∠ACD?

Respuesta :

The isosceles triangle having an angle bisector [tex]\overline{AD}[/tex] forms two congruent triangles.

  • ΔBAD ≅ ΔCAD, therefore, ∠ABD ≅ ΔBAD, by CPCTC

Reasons:

The given parameters are;

ΔABC is an isosceles triangle.

[tex]\overline{AB}[/tex] ≅ [tex]\overline{AC}[/tex]

[tex]\overline{AD}[/tex] bisects ∠BAC

Therefore, the proof that ∠ABD  ≅ ∠ACD is given as follows;

1. [tex]\overline{AB}[/tex] ≅ [tex]\mathbf{\overline{AC}}[/tex] (Given)

2. [tex]\overline{AD}[/tex] bisects ∠BAC (Given)

3. ∠BAD ≅ ∠CAD (Definition of angle bisector)

4. [tex]\overline{AD}[/tex] ≅ [tex]\mathbf{\overline{AD}}[/tex] (Reflexive property of congruency)

5. ΔBAD ≅ ΔCAD (Side Angle Side, SAS rule of congruency based on steps 1, 3 and 4)

6. ∠ABD ≅ ∠ACD (Congruent Parts of Congruent Triangle are Congruent, CPCTC)

Learn more about SAS rule of congruency here:

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