How many carbon atoms are in 11.2 ML of C3H6O

1 mL = 0.815 g
11.2 mL = X
X = 11.2 × 0.815
= 9.128 g
mole = 9.128/58
= 0.157 mole
1 mole = 6.02 × 10^23 atoms
0.157 mol = x
X = 0.157/1 × 6.02 × 10^23
= 9.451 × 10^22 atoms of C
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