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The work done by an electric force in moving a charge from point A to point B is 2.70 × 10‒3 J. The electric potential difference between the two points is VA ‒ VB = 50.0 V. What is the charge?

Respuesta :

Lanuel

The charge moved by this electric force is [tex]5.4 \times 10^{-5} \; Coulombs[/tex].

Given the following data:

  • Work done = [tex]2.70 \times 10^{-3}\;Joules[/tex]
  • Potential difference = 50.0 Volts

To determine the charge:

Mathematically, the work done by an electric force in moving a charge from one point to another is given by the formula:

[tex]W = PQ[/tex]

Where:

  • W is the work done.
  • P is the electric potential difference.
  • Q is the charge.

Making Q the subject of formula, we have:

[tex]Q =\frac{W}{P}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Q =\frac{2.70 \times 10^{-3}}{50}\\\\Q =5.4 \times 10^{-5} \; Coulombs[/tex]

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