Answer:
a. 550 gallons/hr.
b. 1925 gallons
c. 1.268 hours
d. 3.5 hours
Step-by-step explanation:
W = -275(2t-7), where t is hours since pumping starts. Let's rewrite this in standard line format of y = mx + b, where m is the slope and b the y-intercept (the value of y when x = 0). In this case we'll use W and t instead of x and y.
W = -275(2t-7)
W = -550t + 1925
The 1925 figure represents the water volume when t = 0, the initial volume. The slope of -550 is the rate at which water is being pumped out. 550 gallons/hr.
We can solve the equation for the hours required to make w=0:
W = -550t + 1925
0 = -550t + 1925
550t = 1925
t = 3.5 hours
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We can solve for when W = 1,000:
W = -550t + 1925
1000 = -550t + 1925
-925 = -550t
t = 1.682 hours
a. 550 gallons/hr.
b. 1925 gallons
c. 1.268 hours
d. 3.5 hours
We can also graph the function. attached.
