Using the given roots, it is found that on the interval [tex]-\frac{3}{4} < x < 1[/tex], the function is positive.
The function is:
[tex]f(x) = (x - 1)(4x + 3)(3x - 8)[/tex]
The zeroes are:
[tex]x = -\frac{3}{4}, x = 1, x = \frac{8}{3}[/tex]
Between two zeroes, the function has the same sign, hence, to find the sign on the interval [tex]-\frac{3}{4} < x < 1[/tex], we find the numeric value of the function of a value of x on the interval, for example f(0), for x = 0.
Then:
[tex]f(0) = (0 - 1)[4(0) + 3][3(0) - 8] = (-1)(3)(-8) = 24[/tex]
Since f(0) is positive, the function is positive on the interval [tex]-\frac{3}{4} < x < 1[/tex].
A similar problem, in which it is desired to find the sign of the function, is given at https://brainly.com/question/4787253
