Respuesta :

obinnafavour66

Answer:

5y - 6x = 8 or y = 6x/5 + 8/5

Step-by-step explanation:

let M1= gradient of line AB and M2= gradient of the second line

When two lines are perpendicular, the product of their gradients is -1

i.e, M1M2= -1

M2= -1/M1

A(2,9) and B(8,4)

gradient= (y2-y1)/(x2-x1)

M1= (4-9)/(8-2)

= -5/6

M2= -1÷ -5/6

-1 × -6/5= 6/5

Equation of the line passing through C(-3,-2)

[y-(-2)]/[x-(-3)= 6/5

(y+2)/(x+3)= 6/5

5(y+2)= 6(x+3)

5y+10=6x+18

5y= 6x + 8

y= 6x/5 + 8/5

As per the slope-intercept form of a straight line, the equation of the required line is 5y = 6x + 8.

What is the slope-intercept form of a straight line?

The slope-intercept form of a straight line is: y = mx + c

Here, m = slope of the line , c = y-intercept

What is the relation between the slope of a line perpendicular to another line?

If the slope of a line is 'a', then the slope of the line that is perpendicular to the given line is (- 1/a).

The given coordinates of the points A, B, C are (2, 9); (8, 4); and C(- 3, - 2) respectively.

Therefore, the slope of the line AB is (m)

= (y₂ - y₁)/(x₂ - x₁)

= (4 - 9)/(8 - 2)

= (- 5)/6

Slope of the required line is perpendicular to AB.

Therefore, the slope of the required line is

= - 1/(- 5/6)

= 6/5

This line passes through point C(- 3, - 2).

- 2 = - 3(6/5) + c

⇒ c = -2 + 18/5

⇒ c = 8/5

The equation of the required line is

y = (6/5) x + (8/5)

⇒ 5y = 6x + 8

Learn more about the slope-intercept form of a straight line here: https://brainly.com/question/19465597

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