Respuesta :

plit the second term in 2{x}^{2}-x-12x​2​​ −x−1 into two terms2{x}^{2}+x-2x-1=02x​2​​ +x−2x−1=0
2 Factor out common terms in the first two terms, then in the last two termsx(2x+1)-(2x+1)=0x(2x+1)−(2x+1)=0
3 Factor out the common term 2x+12x+1(2x+1)(x-1)=0(2x+1)(x−1)=0
4 Solve for xxx=-\frac{1}{2},1x=−​2​​1​​ ,1



Decimal Form: -0.5, 1