The base and altitude of the triangular plot are [tex]42m[/tex] and [tex]21m[/tex] respectively.
The perimeter of the square plot having the same area as the triangular plot is [tex]84m[/tex]
a) Calculate the base and altitude of the triangular plot
The relationship between the Total cost of leveling the triangular plot, the cost per unit area, and the area of the triangular plot is
[tex]\text{unit cost}=\frac{\text{total cost}}{\text{area}}\\\\\text{area}=\frac{\text{total cost}}{\text{unit cost}}\\\\=\frac{\text{11025Rs.}\rupee}{25Rs./m^2}=441m^2[/tex]
The formula for calculating the area of a triangle, given the base and altitude is
[tex]\text{area of triangle}=\frac{1}{2}\text{base}\times\text{altitude}[/tex]
From the question
[tex]\text{base}=2\times\text{altitude}[/tex]
so
[tex]\text{area of triangle}=\frac{1}{2}\times 2\times\text{altitude}\times\text{altitude}\\\\\text{area of triangle}=\text{altitude}^2\\441=\text{altitude}^2\\\text{altitude}=\sqrt{441}=21m[/tex]
from this we can get the base
[tex]\text{base}=2\times\text{altitude}\\=2\times21m=42m[/tex]
b) Calculate the perimeter of a square plot having the same area
Since we found the area of the triangular plot to be [tex]441m^2[/tex], we will use this value for the area of the square plot, so that we can obtain the side
[tex]\text{area of square plot}=side^2\\441=side^2\\\sqrt{441}=side=21m[/tex]
Hence, the perimeter is equal to
[tex]perimeter=4\times side\\=4\times21=84m[/tex]
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