The molecular formula of the ethylene glycol is C₂H₆O₂.
From the question given above, the following data were obtained:
Molecular formula = empirical × n = molar mass
[CH₃O]n = 62
[12 + (3×1) + 16]n = 62
31n = 62
Divide both side by 31
n = 62 / 31
n = 2
Molecular formula = [CH₃O]n
Molecular formula = [CH₃O]₂
Molecular formula = C₂H₆O₂
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