Answer:
see explanation
Step-by-step explanation:
Using the sine/ cosine ratios in the right triangle and the exact values
sin30° = [tex]\frac{1}{2}[/tex] , cos30° = [tex]\frac{\sqrt{3} }{2}[/tex] , then
sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{6}{AB}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
AB = 12
cos30° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{AC}{12}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )
2 AC = 12[tex]\sqrt{3}[/tex] ( divide both sides by 2 )
AC = 6[tex]\sqrt{3}[/tex]
