Using distance between two points to find the lengths of the edges of the triangle, the correct option is:
b. Isosceles
The distance between two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], is given by:
[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]
Vertex D is translated 4 units to the right is (9,8).
The lengths of the edges are:
[tex]DN = \sqrt{(9 - (-3))^2 + (8 - 10)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}[/tex]
[tex]DO = \sqrt{(9 - (-3))^2 + (8 - 6)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}[/tex]
[tex]NO = \sqrt{(-3 - (-3))^2 + (10 - 6)^2} = \sqrt{0^2 + 4^2} = 4[/tex]
Two edges of the same length, hence, it is an isosceles triangle, given by option b.
You can learn more about distance between two points at https://brainly.com/question/18345417
