Answer:
[tex]\frac{1}{4}(-3n+\frac{3}{2})[/tex] is [tex]\frac{-6n+3}{8}[/tex]
Step-by-step explanation:
Given that: [tex]\frac{1}{4}(-3n+\frac{3}{2})[/tex] ......[1]
The distributive property says that:
[tex]a.(b+c)=a.b+a.c[/tex]
Apply distributive property on [1] we have;
[tex]=\frac{1}{4}.(-3n)+\frac{1}{4}.\frac{3}{2}[/tex]
Simplify:
[tex]=\frac{-3n}{4}+\frac{3}{8}[/tex]
[tex]=\frac{-6n+3}{8}[/tex]
Therefore, the expression that shows the result of applying the distributive property to [tex]\frac{1}{4}(-3n+\frac{3}{2})[/tex] is [tex]\frac{-6n+3}{8}[/tex]
