Answer: 4.544 grams of chlorine gas is produced in the given reaction.
Explanation: Number of moles can be calculated by using the formula:
[tex]Moles=\frac{\text{given mass}}{\text{Molar mass}}[/tex] ... (1)
Molar mass of NaCl = 58.5 g/mol
Given mass of NaCl = 7.5 grams
Moles of NaCl is calculated by:
[tex]Moles=\frac{7.5g}{58.5g/mol}[/tex]
Moles of NaCl = 0.128 moles
The given equation is not balanced. For any further calculation, we first need to balance the equation.
The balanced chemical equation follows:
[tex]2NaCl+2H_2O\rightarrow 2NaOH+Cl_2+H_2[/tex]
By Stoichiometry,
2 moles of NaCl produce 1 mole of chlorine gas
So, 0.128 moles of NaCl will produce = [tex]\frac{1}{2}\times 0.128[/tex] = 0.064 moles of chlorine gas
Mass of Chlorine gas is calculated by using equation 1, we get
Molar mass of [tex]Cl_2[/tex] = 71 g/mol
Putting the values in above equation, we get
[tex]0.064mol=\frac{\text{Given mass}}{71g/mol}[/tex]
Mass of [tex]Cl_2[/tex] produced = 4.544 grams