Respuesta :

it would be 16 i say
[tex](4x+3)(x-7)=90\\ Distribute\\ 4x^{2}-28x+3x-21=90\\ 4x^{2}-25x-21=90\\ 4x^{2}-25x-101=0\\ \\ 101\ is\ a\ prime\ number,\ so\ use\ the\ quadratic\ equation.\\ x= \frac{-b+-\sqrt{b^{2}-4ac}}{2a} \\ \frac{-(-25)+-\sqrt{(-25)^{2}-4*4*(-101)}}{2*4} \\ \frac{25+-\sqrt{625+1616}}{8} \\ x= \frac{25+-\sqrt{2241}}{8} \\ So\ x= \frac{25+\sqrt{2241}}{8}\ and x= \frac{25-\sqrt{2241}}{8} \\ These\ come\ out\ to\ be\ x=9.0424... \ and\ x=-2.7924...[/tex]