Molar mass of chloroform (CHCl3)
C = 1 * 12 = 12 a.m.u
H = 1 * 1 = 1 a.m.u
Cl = 3 * 35.5 = 106.5 a.m.u
Molar Mass (CHCl3) = 12 + 1 + 106.5 = 119.5 g / mol
Knowing that:
The value of Avogadro's constant corresponds to approximately [tex]6,02*10^{23}[/tex] molecules, if chloroform contains [tex]1,00 * 10^{12}[/tex] molecules.
We have:
[tex]1,00 * 10^{12} * 6,02 * 10^{23} = 6,02 * 10 ^ {35} molecules [/tex]
Now, how many grams are there in the chloroform molecule?
grams -------- molecules
119,5 → [tex]6,02 * 10^{23} [/tex]
x → [tex]6,02 * 10^{35} [/tex]
[tex]6,02 * 10 ^ {23} * x = 119,5 * 6,02 * 10 ^{35}[/tex]
[tex]6,02 * 10 ^ {23}x = 719,39 * 10^{35}[/tex]
[tex]x = \frac{719,39}{6,02}*10^{35-23} [/tex]
[tex]\boxed{x = 119,5*10^{12}grams}[/tex]
