Solution = 5,500g
NaOH = 22% of 5,500g
Therefore mass of NaOH is :
0.22 × 5,500g
1,210g
Meaning 1,210 grams inside the solution is Sodium hydroxide
The mass of sodium hydroxide in a solution that has a total mass of 5,500g and is 22% NaOH by mass is 121,000 g.
Mass percent of any substance present in any solution will be calculated as:
Mass % = (Mass of substance) / (Mass of solution)
In the question given that,
Mass percent of NaOH = 22%
Mass of solution = 5,500 g
On putting these values on the above equation we get,
Mass of NaOH = (22)×(5,500) = 121,000 g
Hence required mass of NaOH is 121,000 g.
To know more about mass percent, visit the below link:
https://brainly.com/question/10031774
