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A crash test dummy with a mass of 55kg is placed into a car traveling at 40m/s. During the first trial the dummy does not wear a seatbelt and comes to rest in a time of 0.2 seconds. In the second trial, the dummy wears a seatbelt and comes to rest in a time of 0.5 seconds. Calculate the force experienced by the dummy with and without a seatbelt.

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Lanuel

a. The force experienced by the dummy with a seatbelt is 11,000 Newton.

b. The force experienced by the dummy without a seatbelt is 4,400 Newton.

Given the following data:

  • Mass = 55 kg
  • Initial velocity = 0 m/s
  • Final velocity = 40 m/s
  • Time A = 0.2 seconds
  • Time B = 0.5 seconds

a. To calculate the force experienced by the dummy with a seatbelt:

Newton's Second Law of Motion

In order to solve for the force acting on the dummy, we would apply Newton's Second Law of Motion.

Note: The acceleration of an object is equal to the rate of change in velocity with respect to time.

Mathematically, Newton's Second Law of Motion is given by this formula;

[tex]F = \frac{M(v\;-\;u)}{t}[/tex]

Substituting the given parameters into the formula, we have;

[tex]F = \frac{55(40\;-\;0)}{0.2}\\\\F = \frac{55\times 40}{0.2}\\\\F = \frac{2200}{0.2}[/tex]

Force = 11,000 Newton.

b. To calculate the force experienced by the dummy without a seatbelt:

[tex]F = \frac{55(40\;-\;0)}{0.5}\\\\F = \frac{55\times 40}{0.5}\\\\F = \frac{2200}{0.5}[/tex]

Force = 4,400 Newton.

Read more on force here: https://brainly.com/question/1121817

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