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The spring of a toy car is wound by pushing the car
backward with an average force of 15 newtons through
a distance of 0.50 meter. How much elastic potential
energy is stored in the car's spring during this process?

Respuesta :

Eduard22sly

The elastic potential energy stored in the car's spring during the process is 3.75 J

Determination of the spring constant

From the question given above, the following data were obtained:

  • Force (F) = 15 N
  • Extention (e) = 0.5 m
  • Spring constant (K) =?

K = F/e

K = 15 / 0.5

K = 30 N/m

Determination of the potential energy

  • Spring constant (K) = 30 N/m
  • Extention (e) = 0.5 m
  • Potential energy (PE) =?

PE = ½Ke²

PE = ½ × 30 × 0.5²

PE = 15 × 0.25

PE = 3.75 J

Therefore, the elastic potential energy stored in the car's spring during the process is 3.75 J

Learn more about energy stored in spring:

https://brainly.com/question/4280346

7.5 Joules is the amount of elastic potential energy stored in the car's spring during this process.

w=Fd

w=(15)(0.5)

w = 7.5

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