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For a project in her Geometry class, Kaj uses a mirror on the ground to measure the height of her school building. She walks a distance of 6.15 meters from the building, then places a mirror flat on the ground, marked with an X at the center. She then walks 3.6 more meters past the mirror, so that when she turns around and looks down at the mirror, she can see the top of the school clearly marked in the X. Her partner measures the distance from her eyes to the ground to be 1.35 meters. How tall is the school? Round your answer to the nearest hundredth of a meter.

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MrRoyal

The height of the building is 2.31 meters

Mirror

Kaj's geometry project using the mirror illustrates the use of equivalent ratio.

Given that:

  • Height = 1.35
  • Distance = 3.6 meters
  • Distance 2 = 6.15 meters

Equivalent ratio

From the above parameters, we can derive the following equivalent ratio

[tex]1.35 : 3.6 = h : 6.15[/tex]

Where h represents the height of the school building.

So, we have:

[tex]\frac{1.35 }{ 3.6 }= \frac{h }{ 6.15}[/tex]

Make h the subject

[tex]h =\frac{1.35 }{ 3.6 }\times 6.15[/tex]

[tex]h =2.31[/tex]

Hence, the height of the building is 2.31 meters

Read more about equivalent ratios at:

https://brainly.com/question/2328454