4 A hot air balloon is cruising at an altitude of 120 meters above the ground when it begins its descent. The balloon descends at a rate of 4.5 meters per minute. Explain how you would set up an equation to model when the
balloon will reach an altitude of 75 meters above the ground. Then solve the
equation and check your solution.

Respuesta :

The height of the balloon with time is given by a linear function, given that

the rate at which the balloon descends is constant.

Correct responses:

The equation that models when the balloon will reach an altitude of 75 meters is; 75 = 120 - 4.5·t

The time it takes for the balloon to reach 75 meters is 10 minutes

Methods used to arrive at the above responses

Given parameters:

Initial height of the hot air balloon, h = 120 meters

Rate at which the balloon descends, m = 4.5 meters per minute

Required:

Details of how an equation that models when the balloon reaches an altitude of 75 meters can be set up.

Solution:

Given that the rate at which the balloon descends is constant (4.5 m/min), we have the equation is a linear equation of the form;

y = b

Where:

y = h = The height of the balloon

m = The rate at which the balloon descends = -4.5 m/min (The negative sign indicates that the height is decreasing).

x = t = The time the balloon has been descending.

c = The height of the balloon when x = t = 0, which is the initial height of the balloon = 120 meters

Therefore, we have;

h = m·t + c

Which gives;

Height of the balloon, h = -4.5·t + 120

h = 120 - 4.5·t

When the height, h = 75 meters, we get;

75 = 120 - 4.5·t

The equation that models when the balloon will reach 75 meters above the ground is therefore;

  • 75 = 120 - 4.5·t

The solution of the above equation is found as follows;

4.5·t = 120 - 75 = 45

[tex]\displaystyle t = \frac{45}{4.5} = \mathbf{ 10}[/tex]

  • The time after which the balloon will be at an altitude of 75 meters is t = 10 minutes

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