HELP!! Question in picture!
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Answer:
factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
common factors of both:
1, 2, 3, 4, 6, and 12
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Answer:
[tex]24 {m}^{3} {n}^{5} = {2}^{3} \times 3 \times {m}^{3} \times {n}^{5} \\ 36 {m}^{2} {n}^{3} = {2}^{2} \times {3}^{2} \times {m}^{2} \times {n}^{3} \\ [/tex]
Common Factora =
[tex] {2}^{2} \times 3 \times {m}^{2} \times {n}^{3} \\ 12 {m}^{2} {n}^{3} \\ [/tex]